Battery mAh versus Wh: different voltages, no comparison

A 10,000mAh power bank can't charge a 3,000mAh phone three times, and that's not false advertising but a units problem. The 10,000mAh is rated at 3.7V; convert to 5V and subtract the losses, and you get about two charges.

Last updated: 2026-10-28 BatterymAhWhBattery power

mAh is charge, Wh is energy

mAh (milliamp-hours) is "how many mA for how many hours", an amount of charge. Wh (watt-hours) multiplies in the voltage to give energy: Wh = Ah × V. A 3,000mAh lithium-ion cell (nominal 3.7V) holds 11.1Wh; the same 3,000mAh in NiMH (1.2V) holds only 3.6Wh, a third of the energy.

Compare by mAh only between batteries of the same voltage; otherwise multiply by the nominal voltage to get Wh. Airline carry-on limits are written in Wh too: no restriction under 100Wh, airline approval from 100 to 160Wh (100Wh is 27,000mAh at 3.7V).

Comparing a battery’s charge capacity and stored energy
Comparing a battery’s charge capacity and stored energy. AI-generated conceptual illustration; see the article’s diagrams and text for circuit details and conditions.

Where does a power bank's 10,000mAh go?

The stated capacity is the internal cells' value at 3.7V: 10,000mAh × 3.7V = 37Wh. At 5V that is 37Wh / 5V = 7,400mAh of charge. Nothing was lost; the current (charge) dropped because the voltage went up.

At 90% boost efficiency, 37 × 0.9 / 5 = 6,700mAh.

The phone also loses 10–15% stepping down, so the 5V-side charge needed for a 3,000mAh phone is 3,000 × 3.7 / 5 / 0.87 ≈ 2,550mAh. 6,700 / 2,550 ≈ 2.6 charges, not "10,000 / 3,000 = 3.3."

Breaking down a 10,000mAh power bank's usable capacity
StageVoltageChargeEnergy
Cell (rated capacity)3.7V10000mAh37Wh
Converted to 5V output5V7400mAh37Wh
Boost conversion loss (90% eff.)5V6700mAh33.3Wh
Phone-side charging loss (87%)3.7Vequiv. 7830mAh29Wh
Charging a 3000mAh phone-about 2.6 times-
From 10,000mAh down to the charge available at 5V outputA flow diagram of four boxes connected by arrows: the cell's 10,000mAh at 3.7V -> 37Wh -> converted to 5V, 7,400mAh -> 90% boost efficiency, 6,700mAh. Below, a calculation of how many times that can charge a 3,000mAh phone. mAh becomes a different number the moment the voltage changes A power bank's stated capacity versus the charge actually available at USB output Cell rating 10000mAh 3.7V x 3.7V Energy 37Wh = 10Ah x 3.7V / 5V Converted to 5V 7400mAh = 37Wh / 5V x 0.9 Boost loss 6700mAh 90% efficiency Charging a 3000mAh phone The charging side also has a 5V-to-cell-voltage conversion loss (about 87% efficient). Charge needed at 5V per charge = 3000 x 3.7 / 5 / 0.87 = approx. 2550mAh. 6700 / 2550 = approx. 2.6 charges. Not "10000 / 3000 = 3.3 charges."
Figure 1: from 10,000mAh to 6,700mAh at 5V.

LDO versus DC-DC changes run time

An LDO (linear regulator) has input current equal to output current, and the voltage difference becomes heat. Drawing 50mA at 3.3V from a 3.7V lithium-ion cell also draws 50mA from the battery: 60 hours at 3,000mAh.

A DC-DC (switching) converter works on power: input current = output power / (input voltage × efficiency). At 90% the battery draws 3.3 × 0.05 / (3.7 × 0.9) = 49.5mA, nearly the same as the LDO.

The difference shows up when the output voltage is much lower than the input. Drawing 50mA at 1.8V from 3.7V, an LDO draws 50mA (60 hours) while a 90%-efficient DC-DC draws 1.8 × 0.05 / (3.7 × 0.9) = 27mA, or 111 hours, roughly double. With a small difference like 3.7V to 3.3V, the DC-DC's quiescent current (tens of µA to a few mA) can make the LDO last longer under light load.

Battery current and run time: LDO vs DC-DCBar chart for drawing 50mA at 1.8V from 3.7V: the LDO draws 50mA from the battery for 60 hours; a 90%-efficient DC-DC draws 27mA for 111 hours. With a large voltage drop, a DC-DC nearly halves the battery current Drawing 50mA at 1.8V from 3.7V; 3000mAh battery Current from the battery Run time LDO In = out current, rest is heat 50mA 60 hours DC-DC (90% eff.) Iin = Pout / (Vin × eff.) 27mA 111 hours From 3.7V to 3.3V it is 50mA vs 49.5mA, nearly the same.
Figure 2: battery current and run time when drawing 50mA at 1.8V from 3.7V.

Capacity you can't use: the cutoff voltage

A lithium-ion cell's rated 3,000mAh is measured from 4.2V down to 2.5–3.0V. An LDO outputting 3.3V with a 0.3V dropout can't hold the output once the battery falls below 3.6V, so capacity remaining below 3.6V is unusable.

Most of the capacity sits at 3.5–3.9V and only 20–30% remains below 3.6V, so a 3.6V cutoff gets 2,100–2,400mAh of the rated 3,000mAh.

The fixes are to lower the circuit's voltage, use a low-dropout LDO (0.1V or less), or use a buck-boost converter to run the cell down to 2.5V.

Discharge curve and the cutoff voltageA schematic lithium-ion discharge curve of battery voltage against discharged capacity. It falls from 4.2V, and 20–30% of the capacity remains below the 3.6V line. A 3.3V LDO with 0.3V dropout can't use that part. Capacity left below 3.6V is unusable with a 3.3V LDO Lithium-ion discharge curve (schematic) 4.2V 3.6V 3.3V + 0.3V dropout 2.5–3.0V Capacity discharged → Cell voltage Usable Unusable 20–30% Of the 3000mAh, only 2100–2400mAh is usable (with a 3.6V cutoff)
Figure 3: schematic discharge curve. The 20–30% remaining below 3.6V can't be used with a 3.3V LDO.

Temperature and discharge current shrink it further

  • Low temperature. A lithium-ion cell holds about 80% of its room-temperature capacity at 0°C and 50–60% at −20°C, and its internal resistance rises, so it hits cutoff sooner.
  • Discharge current. Rated capacity is measured around 0.2C (5-hour rate). At 1C it drops a few percent, and a lead-acid battery over 20% (Peukert's law).
  • Pulse loads and coin cells. A CR2032 (225mAh, 3V) has an internal resistance of 10–40 ohm, so a 30mA radio pulse sags it by 0.3–1.2V and can trigger a reset. A parallel capacitor (100µF or more) can supply the pulse.
  • Self-discharge. Lithium-ion loses 2–3% per month, NiMH 15–20% per month (15% per year for low-self-discharge cells), alkaline 2–3% per year.
  • Aging. A lithium-ion cell drops to about 80% after 500 cycles, so calculate against 70–80% of initial capacity to guarantee run time at end of life.

Estimating with the calculator

Use the mAh-to-Wh calculator to get the battery's energy and divide by the device's power consumption (including conversion efficiency) for a rough run time. Multiplying in the unusable capacity, temperature, and aging, real run time is 50–70% of that. For charging cost, use the electricity cost calculator: a 37Wh power bank fully charged at 45Wh including losses, at 31 yen/kWh, costs about 1.4 yen.

Frequently asked questions

Does a higher mAh battery last longer?
Yes, if the voltage is the same; otherwise compare in Wh. A 1,500mAh lithium-ion cell (5.6Wh) holds more energy than a 3,000mAh NiMH cell (3.6Wh).
What's the difference between a power bank's "rated capacity" and "capacity"?
"Capacity" is the internal cell's value at 3.7V; "rated capacity" is what you can draw at the 5V USB output, about 60–70% of the former after conversion losses.
For battery power, should I use an LDO or a DC-DC converter?
If the output is 70–80% or more of the input (e.g. 3.7V to 3.3V), an LDO is fine. If it is half the input or less (3.7V to 1.8V), a DC-DC can nearly double run time. With microamp-level standby current the DC-DC's own consumption dominates.
Down to what voltage can I use a lithium-ion cell?
The cell's cutoff is 2.5–3.0V, but a 3.3V LDO bottoms out around 3.6V. To use the cell down further, use a buck-boost converter, matched to the operating voltage of the protection circuit (which cuts off on over-discharge).

Standards and references

  • IEC 61960 — Capacity measurement conditions for secondary lithium cells (discharge rate, cutoff voltage)
  • IATA Dangerous Goods Regulations — Wh-based classification for air transport of lithium batteries
  • Battery manufacturers' datasheets — Discharge curves, temperature characteristics, cycle life, and self-discharge rates

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