Battery mAh versus Wh: different voltages, no comparison

A 10,000mAh power bank can't fully charge a 3,000mAh phone three times over, and that's not false advertising — it's a units problem. The 10,000mAh is rated at 3.7V; convert that to 5V and it becomes 7,400mAh, conversion losses bring it to 6,700mAh, and losses on the charging side bring it down to about two charges.

Last updated: 2026-09-14 BatterymAhWhBattery power

mAh is charge, Wh is energy

mAh (milliamp-hours) is "how many mA for how many hours" — an amount of charge. Wh (watt-hours) is energy, obtained by multiplying in the voltage: Wh = Ah x V. A 3,000mAh lithium-ion cell (nominal 3.7V) holds 11.1Wh. The same 3,000mAh in a NiMH cell (1.2V) holds only 3.6Wh — a third of the energy.

Use Wh to compare what's actually inside a battery. Comparing by mAh alone is valid only between batteries of the same voltage. If a datasheet lists only mAh, multiply by the nominal voltage to get Wh before comparing.

This is why airline carry-on limits are written in Wh, not mAh: no restriction under 100Wh, airline approval required between 100 and 160Wh. At 3.7V, 100Wh corresponds to 27,000mAh.

Where does a power bank's 10,000mAh go?

A power bank's stated capacity is the value of its internal lithium-ion cells at 3.7V: 10,000mAh x 3.7V = 37Wh. Delivering that through USB at 5V requires boost conversion, and as charge that becomes 37Wh / 5V = 7,400mAh. It hasn't shrunk — the current (charge) has dropped because the voltage went up.

With a boost converter running at 90% efficiency, what actually comes out at 5V is 37 x 0.9 / 5 = 6,700mAh. Some products print this figure alongside the raw one, labeled something like "rated capacity: 6,700mAh."

The phone side has its own loss (10-15%) stepping 5V down to the cell's 3.7-4.2V for charging. The charge needed at the 5V side to charge a 3,000mAh phone is 3,000 x 3.7 / 5 / 0.87 ≈ 2,550mAh, so 6,700 / 2,550 ≈ 2.6 charges — not the "10,000 / 3,000 = 3.3 charges" naive division suggests.

Breaking down a 10,000mAh power bank's usable capacity
StageVoltageChargeEnergy
Cell (rated capacity)3.7V10000mAh37Wh
Converted to 5V output5V7400mAh37Wh
Boost conversion loss (90% eff.)5V6700mAh33.3Wh
Phone-side charging loss (87%)3.7Vequiv. 7830mAh29Wh
Charging a 3000mAh phone-about 2.6 times-
From 10,000mAh down to the charge available at 5V outputA flow diagram of four boxes connected by arrows: the cell's 10,000mAh at 3.7V -> 37Wh -> converted to 5V, 7,400mAh -> 90% boost efficiency, 6,700mAh. Below, a calculation of how many times that can charge a 3,000mAh phone. mAh becomes a different number the moment the voltage changes A power bank's stated capacity versus the charge actually available at USB output Cell rating 10000mAh 3.7V x 3.7V Energy 37Wh = 10Ah x 3.7V / 5V Converted to 5V 7400mAh = 37Wh / 5V x 0.9 Boost loss 6700mAh 90% efficiency Charging a 3000mAh phone The charging side also has a 5V-to-cell-voltage conversion loss (about 87% efficient). Charge needed at 5V per charge = 3000 x 3.7 / 5 / 0.87 = approx. 2550mAh. 6700 / 2550 = approx. 2.6 charges. Not "10000 / 3000 = 3.3 charges."
Figure 1: from a power bank's 10,000mAh down to what actually comes out at 5V, 6,700mAh. What's lost isn't energy so much as charge given up to the higher voltage, plus conversion losses.

LDO versus DC-DC changes run time

When a battery powers a device, the way its voltage is converted to the circuit's voltage changes how long it runs.

LDO (linear regulator). Input current equals output current; the voltage difference becomes heat. Drawing 50mA at 3.3V from a 3.7V lithium-ion cell also draws 50mA from the battery. At 3,000mAh, that's 60 hours. Efficiency is 3.3/3.7 = 89%, but it shifts with cell voltage: 79% at 4.2V, 94% at 3.5V.

DC-DC (switching converter). Conversion works on power, so input current = output power / (input voltage x efficiency). Under the same conditions at 90% efficiency, the battery draws 3.3 x 0.05 / (3.7 x 0.9) = 49.5mA — nearly identical to the LDO.

The difference shows up when the output voltage is much lower than the input. Drawing 50mA at 1.8V from 3.7V, an LDO still draws 50mA (60 hours), while a 90%-efficient DC-DC draws 1.8 x 0.05 / (3.7 x 0.9) = 27mA, giving 111 hours — roughly double. Conversely, with a small voltage difference like 3.7V to 3.3V, the DC-DC's fixed overhead (tens of µA to a few mA of quiescent current) can make the LDO last longer under light load.

Capacity you can't use: the cutoff voltage

A lithium-ion cell's rated 3,000mAh is measured discharging from 4.2V down to 2.5-3.0V. But if the circuit's LDO outputs 3.3V with a 0.3V dropout, it can't hold the output once the battery drops below 3.6V. Whatever capacity remains below 3.6V is simply unusable.

Most of a lithium-ion cell's capacity sits in the 3.5-3.9V range of its discharge curve, and only 20-30% remains below 3.6V. So a design with a 3.6V cutoff only gets to use 2,100-2,400mAh of the rated 3,000mAh.

The fixes are: lower the circuit's operating voltage (3.3V to 3.0V, or 1.8V), use a low-dropout LDO (0.1V or less), or use a buck-boost converter to run the cell all the way down to 2.5V. In a battery-powered design, "down to what voltage does it still run" translates directly into run time.

Temperature and discharge current shrink it further

  • Low temperature. A lithium-ion cell holds about 80% of its room-temperature capacity at 0°C, and 50-60% at -20°C. Internal resistance also rises, so under a heavy load the voltage sags further and the cell hits cutoff sooner.
  • Discharge current. Rated capacity is measured around 0.2C (5-hour rate). At 1C (1-hour rate) capacity drops a few percent; a lead-acid battery can drop over 20% (Peukert's law). At very low currents, you can pull out more than the rated value.
  • Pulse loads and coin cells. A CR2032 (225mAh, 3V) has an internal resistance of 10-40 ohm; a radio module pulling a 30mA pulse can sag it by 0.3-1.2V. Even with plenty of average current margin, a voltage sag during the pulse can trigger a reset. A parallel capacitor (100µF or more) can supply the pulse instead.
  • Self-discharge. Lithium-ion loses 2-3% per month, NiMH 15-20% per month (15% per year for low-self-discharge cells), alkaline 2-3% per year. For equipment left idle for a year or more, factor this into the run-time calculation.
  • Aging. A lithium-ion cell drops to about 80% of capacity after 500 cycles. If you need to guarantee run time at end of life, calculate against 70-80% of the initial rated capacity.

Estimating with the calculator

Use the mAh-to-Wh calculator to get the battery's energy, then divide by the device's power consumption (voltage x current, including conversion efficiency) for a rough run-time estimate. From there, multiply in the unusable capacity (cutoff voltage), temperature, and aging factors — it's safe to assume real run time comes out to 50-70% of that rough number.

You can estimate charging cost with the electricity cost calculator. Fully charging a 37Wh power bank at 45Wh including charging losses, at 31 yen/kWh, costs about 1.4 yen.

Frequently asked questions

Does a higher mAh battery last longer?
Yes, if the voltage is the same. If voltages differ, compare in Wh instead. A 1,500mAh lithium-ion cell (3.7V, 5.6Wh) holds more energy than a 3,000mAh NiMH cell (1.2V, 3.6Wh).
What's the difference between a power bank's "rated capacity" and "capacity"?
"Capacity" is the internal cell's value at 3.7V; "rated capacity" is what you can actually draw out at the USB output (5V). The latter includes conversion losses and comes to about 60-70% of the former.
For battery power, should I use an LDO or a DC-DC converter?
If the output voltage is 70-80% or more of the input (e.g. 3.7V to 3.3V), the difference is small, and an LDO's lower part count and lower noise are fine. If the output is half the input or less (e.g. 3.7V to 1.8V), a DC-DC can nearly double run time. But in a device with microamp-level standby current, the DC-DC's own quiescent current can dominate, so pick a low-quiescent-current part or stick with an LDO.
Down to what voltage can I use a lithium-ion cell?
The cell's own spec puts the discharge cutoff at 2.5-3.0V. But the circuit has to actually run at that voltage — a 3.3V LDO typically bottoms out around 3.6V. To use the cell down further, use a buck-boost converter, matched to the operating voltage of the protection circuit (which cuts off on over-discharge).

Standards and references

  • IEC 61960 — Capacity measurement conditions for secondary lithium cells (discharge rate, cutoff voltage)
  • IATA Dangerous Goods Regulations — Wh-based classification for air transport of lithium batteries
  • Battery manufacturers' datasheets — Discharge curves, temperature characteristics, cycle life, and self-discharge rates

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